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(2-x)^3+(3+x)(9-3x+x^2)+6x(1-x)=17
We move all terms to the left:
(2-x)^3+(3+x)(9-3x+x^2)+6x(1-x)-(17)=0
We add all the numbers together, and all the variables
(x+3)(9-3x+x^2)+(-1x+2)^3+6x(-1x+1)-17=0
We multiply parentheses
(x+3)(9-3x+x^2)-6x^2+(-1x+2)^3+6x-17=0
We add all the numbers together, and all the variables
-6x^2+(x+3)(9-3x+x^2)+6x+(-1x+2)^3-17=0
We move all terms containing x to the left, all other terms to the right
-6x^2+(x+3)(9-3x+x^2)+6x+(-1x+2)^3=17
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